Django-filter: 使用 OR 条件过滤多个字段

感谢您打开这个，这与我的问题完全相同。

目前，我收到以下警告：

/usr/local/lib/python3.7/site-packages/django_filters/rest_framework/backends.py:128: 
UserWarning: <class 'project.api.views.FooBarViewSet'> is not compatible with schema generation

我有一个看起来像这样的 FilterSet 和 ViewSet：

# models
class FooBarUserAssignment(models.Model):
    user = models.ForeignKey("auth.User", on_delete=models.CASCADE)
    foobar = models.ForeignKey("FooBar", on_delete=models.CASCADE)

    class Meta:
        unique_together = (
            ("user", "foobar"),
        )


class FooBarGroupAssignment(models.Model):
    group = models.ForeignKey("auth.Group", on_delete=models.CASCADE)
    foobar = models.ForeignKey("FooBar", on_delete=models.CASCADE)

    class Meta:
        unique_together = (
            ("group", "foobar"),
        )

class FooBar(models.Model):
    title = models.CharField(max_length=160, unique=True)

    users = models.ManyToManyField(
        to="auth.User",
        through=FooBarUserAssignment,
    )
    groups = models.ManyToManyField(
        to="auth.Group",
        through=FooBarGroupAssignment,
    )

    def __str__(self):
        return self.title

# filters
from django_filters import rest_framework as rest_framework_filters

class FooBarFilter(rest_framework_filters.FilterSet):
    title = rest_framework_filters.CharFilter(field_name="title", lookup_expr="icontains")

    class Meta:
        model = FooBar
        fields = ("title", )

# viewsets
class FooBarViewSet(ModelViewSet):
    queryset = Foobar.objects.order_by("-title")
    serializer_class = FooBarSerializer
    filterset_class = FooBarFilter

    def get_queryset(self):
        queryset = self.queryset

        q_name = Q()
        rel_name = self.request.query_params.get("rel_name", None)
        if rel_name:
            q_name = Q(users__name=rel_name)

        q_groups = Q()
        rel_groups = self.request.query_params.get("rel_groups", "").split(",")
        if any(rel_groups):
            q_groups = Q(groups__name__in=rel_groups)

        qs = queryset.filter(q_name | q_groups).distinct()
        return qs

我如何构建一个 FilterSet 来执行完全相同的查询？
我能够实现部分FilterSet，但仍然不知道将OR逻辑从ViewSet.get_queryset()移动到FilterSet的最佳方法是什么

import django_filters
from django_filters import rest_framework as rest_framework_filters

class CharInFilter(django_filters.BaseInFilter, rest_framework_filters.CharFilter):
    pass

class FooBarFilter(rest_framework_filters.FilterSet):
    title = rest_framework_filters.CharFilter(field_name="title", lookup_expr="icontains")
    rel_name = rest_framework_filters.CharFilter(field_name="users__name", lookup_expr="exact")
    rel_groups = CharInFilter(field_name="groups__name")

    class Meta:
        model = FooBar
        fields = ("title", )

    def filter_queryset(self, queryset):
        qs = super().filter_queryset(queryset)
        return qs.distinct()

看起来这是 django-filter 扩展的一部分，可以安装在 django-filter 旁边。 https://github.com/philipn/django-rest-framework-filters#complex -operations

大家好。 我创建了#1167，它应该提供组级验证和过滤。 对于 OP，用法如下所示：

class UserFilter(FilterSet):
    class Meta:
        model = User
        field = ['username', 'first_name', 'last_name']
        groups = [
            CombinedGroup(filters=['first_name', 'last_name'], combine=operator.or_),
        ]

任何关于 PR 的反馈将不胜感激。

这里仍然是同样的问题，他们有解决方案吗？

@JeromeK13看起来什么都不是！ 我有同样的问题

我做了类似以下的事情，我不确定是否适用于所有情况，但解决了我的问题：

class BaseFilter(django_filters.FilterSet):
    def OR(self, queryset, field_name, value):
        if not hasattr(self, "groups"):
            setattr(self, "groups", {})

        self.groups[field_name] = value
        return queryset

    <strong i="6">@property</strong>
    def qs(self):
        base_queryset = super().qs

        if not hasattr(self, "groups"):
            return base_queryset

        query = Q()
        for key, value in self.groups.items():
            query |= Q(**{key: value})

        return base_queryset.filter(query)

class PlanFilter(BaseFilter):
    double_visit__or = django_filters.UUIDFilter("double_visit", method="OR")
    visitor__or = django_filters.UUIDFilter("visitor", method="OR")
    class Meta:
        model = models.Plan
        fields = {
            "id": ["exact"],
            "date": ["exact", "gte", "lte",],
            "visitor": ["exact"],
            "doctor": ["exact"],
            "double_visit": ["exact"]
        }

我相信我找到了一个更简单的方法：

from django.db.models.query_utils import Q
user_contacts = Contact.objects.order_by('-contact_date').filter(Q(sender_id=request.user.user_id)|Q(receiver_id=request.user.user_id)) 

就我而言，我想收集所有具有特殊sender_id或receiver_id的行。 而且，我希望它们在一个查询集中按date排序

你好，
如何使用 OR 条件过滤多个字段！？
例如：
first_name = foo OR last_name = bar
相当于：
model.objects.filter(Q(first_name=foo) | Q(last_name=bar))

进口Q

django.db.models 导入 Q

它对我有用。