Office365-rest-python-client: 如何将文件上传到Sharepoint？

我只用ClientRequest class来做到这一点。

   def upload_binary_file(self, file):
        """Attempt to upload a binary file to SharePoint"""

        folder_url = "folder_to_upload_to"
        text_file = basename(file.name)
        full_url = "{0}/_api/web/GetFolderByServerRelativeUrl('{1}')/Files/add(url='{2}', overwrite=true)".format(self.base_url, folder_url, text_file)
        options = RequestOptions(full_url)
        context = ClientContext(full_url, self.ctx_auth)
        options.set_header('Accept', 'application/json; odata=verbose')
        options.set_header('Content-Type', 'application/octet-stream')
        options.set_header('Content-Length', str(os.path.getsize(file.name)))
        options.set_header('X-RequestDigest', YOUR_FORM_DIGEST)
        options.method = 'POST'
        file_name = file.name        
        with open(file_name, 'rb') as outfile:

            # instead of executing the query directly, we'll try to go around
            # and set the json data explicitly

            context.authenticate_request(options)

            data = requests.post(url=full_url, data=outfile, headers=options.headers, auth=options.auth)
            if data.status_code == 200:
                # our file has uploaded successfully
                # let's return the URL
                base_site = data.json()['d']['Properties']['__deferred']['uri'].split("/sites")[0]
                relative_url = data.json()['d']['ServerRelativeUrl'].replace(' ', '%20')

                return base_site + relative_url
            else:
                return "Log Failed to Upload" 

@benpolinsky感谢您发布摘要，最终我使它起作用了。 起初我很难获取表格摘要，但是一旦我弄清楚了如何做到这一点就可以了。

from office365.runtime.auth.authentication_context import AuthenticationContext
from office365.sharepoint.client_context import ClientContext
from office365.runtime.utilities.request_options import RequestOptions

from office365.sharepoint.file_creation_information import FileCreationInformation
from settings import settings
import requests
import os
from os.path import basename


ctx_auth = AuthenticationContext(url=settings['url'])
if ctx_auth.acquire_token_for_user(username=settings['username'], password=settings['password']):
    upload_binary_file("c:\temp\myfile.txt",ctx_auth)

def upload_binary_file(file_path, ctx_auth):
    """Attempt to upload a binary file to SharePoint"""

    base_url = settings['url']
    folder_url = "MyFolder"
    file_name = basename(file_path)
    files_url ="{0}/_api/web/GetFolderByServerRelativeUrl('{1}')/Files/add(url='{2}', overwrite=true)"
    full_url = files_url.format(base_url, folder_url, file_name)

    options = RequestOptions(settings['url'])
    context = ClientContext(settings['url'], ctx_auth)
    context.request_form_digest()

    options.set_header('Accept', 'application/json; odata=verbose')
    options.set_header('Content-Type', 'application/octet-stream')
    options.set_header('Content-Length', str(os.path.getsize(file_path)))
    options.set_header('X-RequestDigest', context.contextWebInformation.form_digest_value)
    options.method = 'POST'

    with open(file_path, 'rb') as outfile:

        # instead of executing the query directly, we'll try to go around
        # and set the json data explicitly

        context.authenticate_request(options)

        data = requests.post(url=full_url, data=outfile, headers=options.headers, auth=options.auth)

        if data.status_code == 200:
            # our file has uploaded successfully
            # let's return the URL
            base_site = data.json()['d']['Properties']['__deferred']['uri'].split("/sites")[0]
            relative_url = data.json()['d']['ServerRelativeUrl'].replace(' ', '%20')

            return base_site + relative_url
        else:
            return data.json()['error']

我希望有一个简单的api将文件上传到sharepoint。 这太复杂了。

@attibalazs感谢您的脚本。 我确实遇到了以下错误，目前停留在这里：

get_authentication_cookie中的第65行的文件“ C：\ Python27 \ lib \ site-packages \ office365 \ runtime \ auth \ saml_token_provider.py”
返回'FedAuth ='+ self.FedAuth +'; rtFa ='+ self.rtFa
TypeError：无法连接“ str”和“ NoneType”对象

除了SP Online URL，用户名和密码之外，您还需要使用客户端ID和客户端密钥吗？

感谢您的@attibalazs 。 这对我来说很棒。

我怀疑..没有了组织此代码的工作占像[email protected]或者我们需要有一个适当的office365帐户像[email protected] ？

嗨，我使用了@attibalazs脚本，在我尝试在Sharepoint中上传数据之前，该脚本似乎运行良好：
data = requests.post(url=full_url, data=outfile, headers=options.headers, auth=options.auth)

我的状态为403。 我应该在我的办公室帐户配置中进行一些更改以获取以这种方式在Sharepoint中进行写入的权利吗？

@attibalazs
使用API​​。 status = ctx_auth.acquire_token_for_app（），而不是status = ctx_auth.acquire_token_for_user（用户名，密码）
并安装packge。 点安装-U认证

您好，我为您的代码添加了一些对我有用的调整：

我正在尝试将文件上传到共享点，我在正确的路径上吗？

```
def upload_file（ctx，listTitle，path）：
list_obj = ctx.web.lists.get_by_title（listTitle）
文件夹= list_obj.root_folder
ctx.load（文件夹）
ctx.execute_query（）

files = folder.files
    ctx.load(files)
    ctx.execute_query()

with open(path, 'rb') as f:
    content = f.read()
    file_creation_information = FileCreationInformation()
    file_creation_information.overwrite = True
       file_creation_information.url = os.path.basename(path)
    file_creation_information.content = content
    file_new = files.add(file_creation_information)
       ctx.load(files)
       ctx.execute_query()

问候，

由于已解决该问题，因此我建议将其关闭。

总结一下：

下面演示了将文件上传到SharePoint库的推荐方法：

#read a local file
path = "../tests/data/SharePoint User Guide.docx"
with open(path, 'rb') as content_file:
    file_content = content_file.read()

#upload it into Documents library
target_folder = context.web.lists.get_by_title("Documents").rootFolder
info = FileCreationInformation()
info.content = file_content
info.url = os.path.basename(path)
info.overwrite = True
target_file = target_folder.files.add(info)
context.execute_query()

但是，如果文件大于2 MB，则需要将文件作为一组块上载：

ctx = ClientContext(site_url, ctx_auth)
size_1Mb = 1000000
local_path = "./data/big_buck_bunny.mp4"
target_url = "/Shared Documents"
result_file = ctx.web.get_folder_by_server_relative_url(target_url).files.create_upload_session(local_path, size_1Mb, print_upload_progress)
ctx.execute_query()
print('File {0} has been uploaded successfully'.format(result_file.properties['ServerRelativeUrl']))

在哪里

def print_upload_progress(offset):
    print("Uploaded '{0}' bytes...".format(offset))

如果您喜欢自己构建上传请求，那么@attibalazs和@benpolinsky提供的不错的选择。

瓦迪姆