Restsharp: 如何：使用 RestSharp 为复杂对象发送 HTTP Post

创建于 2013-10-04 · 3评论 · 资料来源: restsharp/RestSharp

有人可以建议如何使用以下作为请求参数发送 HTTP Post。

{
    "key": "example key",
    "message": {
        "html": "<p>Example HTML content</p>",
        "text": "Example text content",
        "subject": "example subject",
        "from_email": "[email protected]",
        "from_name": "Example Name",
        "to": [
            {
                "email": "[email protected]",
                "name": "Recipient Name"
            }
        ],
        "headers": {
            "Reply-To": "[email protected]"
        },
        "important": false,
        "track_opens": null,
        "track_clicks": null,
        "auto_text": null,
        "auto_html": null,
        "inline_css": null,
        "url_strip_qs": null,
        "preserve_recipients": null,
        "view_content_link": null,
        "bcc_address": "[email protected]",
        "tracking_domain": null,
        "signing_domain": null,
        "return_path_domain": null,
        "merge": true,
        "global_merge_vars": [
            {
                "name": "merge1",
                "content": "merge1 content"
            }
        ],
        "merge_vars": [
            {
                "rcpt": "[email protected]",
                "vars": [
                    {
                        "name": "merge2",
                        "content": "merge2 content"
                    }
                ]
            }
        ],
        "tags": [
            "password-resets"
        ],
        "subaccount": "customer-123",
        "google_analytics_domains": [
            "example.com"
        ],
        "google_analytics_campaign": "[email protected]",
        "metadata": {
            "website": "www.example.com"
        },
        "recipient_metadata": [
            {
                "rcpt": "[email protected]",
                "values": {
                    "user_id": 123456
                }
            }
        ],
        "attachments": [
            {
                "type": "text/plain",
                "name": "myfile.txt",
                "content": "ZXhhbXBsZSBmaWxl"
            }
        ],
        "images": [
            {
                "type": "image/png",
                "name": "IMAGECID",
                "content": "ZXhhbXBsZSBmaWxl"
            }
        ]
    },
    "async": false,
    "ip_pool": "Main Pool",
    "send_at": "example send_at"
}

我不知道如何使用 RestSharp

资料来源

abishekrsrikaanth

最有用的评论

你好，

1）将您的 JSON 转换为 POCO（http://json2csharp.com/ 非常适合）。
2)
var yourobject = new MyObject{.....................};
var json = JsonConvert.SerializeObject(yourobject);

var client = new RestClient(url);

var request = new RestRequest(actionPath, Method.POST);
request .AddParameter("application/json; charset=utf-8", json, ParameterType.RequestBody);
请求 .RequestFormat = DataFormat.Json;

_client.ExecuteAsync(restRequest, response => ........);

claudiosanchez 于 2013-10-07

👍10 ❤4 🎉2

所有3条评论

你好，

1）将您的 JSON 转换为 POCO（http://json2csharp.com/ 非常适合）。
2)
var yourobject = new MyObject{.....................};
var json = JsonConvert.SerializeObject(yourobject);

var client = new RestClient(url);

var request = new RestRequest(actionPath, Method.POST);
request .AddParameter("application/json; charset=utf-8", json, ParameterType.RequestBody);
请求 .RequestFormat = DataFormat.Json;

_client.ExecuteAsync(restRequest, response => ........);

claudiosanchez 于 2013-10-07

👍10 ❤4 🎉2

也谢谢我！

rodrigoporcionato 于 2017-06-13

对于后代，RestSharp 现在已经为此内置了方法。
查看RestRequest的AddJsonBody()方法
无论如何，这对于 RestSharp 105.0.1.0 及以后的版本都是正确的。

Caltor 于 2018-09-20

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Restsharp: 如何：使用 RestSharp 为复杂对象发送 HTTP Post

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