Sentry-javascript: How to send custom exception correctly?

Created on 9 Nov 2018 · 3Comments · Source: getsentry/sentry-javascript

I'm doing now

       try {
            throw new FormValidationException(node, input);
        } catch (err) {
            Sentry.captureException(err);
        }

But I feel it's wrong.
Is there any other ways to send custom exception?

Question

Source

dimmduh

Most helpful comment

Or just Sentry.captureException(new FormValidationException(node, input)) if you don't need anything inside try block and just want to send custom error.

kamilogorek on 13 Nov 2018

👍2

All 3 comments

Why should this be wrong? This is perfectly fine.

HazAT on 9 Nov 2018

Or just Sentry.captureException(new FormValidationException(node, input)) if you don't need anything inside try block and just want to send custom error.

kamilogorek on 13 Nov 2018

👍2

Main question was answered. Feel free to reopen if still need any help. Cheers!

kamilogorek on 20 Nov 2018

Was this page helpful?

0 / 5 - 0 ratings