Three.js: Wie erstelle ich ein benutzerdefiniertes Netz?

Erstellt am 12. Feb. 2012  ·  3Kommentare  ·  Quelle: mrdoob/three.js

Das hat nicht funktioniert:

var geom = new THREE.Geometry(); 
var v1 = new THREE.Vector3(0,0,10);
var v2 = new THREE.Vector3(0,500,10);
var v3 = new THREE.Vector3(500,500,10);

geom.vertices.push(new THREE.Vertex(v1));
geom.vertices.push(new THREE.Vertex(v2));
geom.vertices.push(new THREE.Vertex(v3));
geom.faces.push( new THREE.Face3( 0, 1, 2 ) );

var object = new THREE.Mesh( geom, new THREE.MeshNormalMaterial() );
scene.addObject(object);
Question

Hilfreichster Kommentar

var geom = new THREE.Geometry(); 
var v1 = new THREE.Vector3(0,0,10);
var v2 = new THREE.Vector3(0,500,10);
var v3 = new THREE.Vector3(500,500,10);

geom.vertices.push(new THREE.Vertex(v1));
geom.vertices.push(new THREE.Vertex(v2));
geom.vertices.push(new THREE.Vertex(v3));
geom.faces.push( new THREE.Face3( 0, 1, 2 ) );
geom.computeFaceNormals(); // your geometry needs normals if you want to use MeshNormalMaterial

var object = new THREE.Mesh( geom, new THREE.MeshNormalMaterial() );
scene.add(object); // scene.addObject is supposed to be used internally only, sorry about that.

Alle 3 Kommentare

var geom = new THREE.Geometry(); 
var v1 = new THREE.Vector3(0,0,10);
var v2 = new THREE.Vector3(0,500,10);
var v3 = new THREE.Vector3(500,500,10);

geom.vertices.push(new THREE.Vertex(v1));
geom.vertices.push(new THREE.Vertex(v2));
geom.vertices.push(new THREE.Vertex(v3));
geom.faces.push( new THREE.Face3( 0, 1, 2 ) );
geom.computeFaceNormals(); // your geometry needs normals if you want to use MeshNormalMaterial

var object = new THREE.Mesh( geom, new THREE.MeshNormalMaterial() );
scene.add(object); // scene.addObject is supposed to be used internally only, sorry about that.

Was für eine schnelle Antwort. Vielen Dank! Arbeiten Sie noch an dem Projekt? Brauchst du etwas?

Jep!

https://github.com/mrdoob/three.js/commits/dev

Ich bin mir nicht sicher, was nötig ist, um ehrlich zu sein ... Ich denke, wir brauchen nur Zeit: D.

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